document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43703>Question 43703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble with a new set of problems. The equation is:<BR>\n" );
document.write( "x+1/2x+3 = 2/3\r<BR>\n" );
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document.write( "I was having help but I can't remeber it all right now. So far I went to <BR>\n" );
document.write( "(2x+3)(x+1/2x+3 = 2/3 (2x+3)<BR>\n" );
document.write( "x+1 = 2/3 (2x/1) + 2/3 (3)<BR>\n" );
document.write( "4x/3 + 6/9- 1\r<BR>\n" );
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document.write( "What do I need to do to finish this equation? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28699 by </B><A HREF=/tutors/aboutme.mpl?userid=jake_6233><B>jake_6233(74)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jake_6233><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have a good start to the problem however remember the idea is to remove denominators \r<BR>\n" );
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document.write( "x+1/2x+3 = 2/3  Remember if a/b=c/d the ac=bd  We have<BR>\n" );
document.write( "3(x+1)=2(2x+3)<BR>\n" );
document.write( "3x+3=4x+6<BR>\n" );
document.write( "-3 =x<BR>\n" );
document.write( "When you plug -3 into the origianal equation you will get -2/-3 which is equivalent </SPAN>\n" );
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