document.write( "Question 406733: Trains A and B are traveling in the same direction on parellel tracks. Train A is traveling at a speed of 40 m.p.h and Train B is traveling at a speed of 50 m.p.h. Train A passes the station at 2:25 p.m. and Train B passes the same station at 2:55 p.m. At this rate, what time will Train B catch up to Train A?
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Algebra.Com's Answer #286976 by ankor@dixie-net.com(22740)\"\" \"About 
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Trains A and B are traveling in the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at a speed of 40 m.p.h and Train B is traveling at a speed of 50 m.p.h.
\n" ); document.write( " Train A passes the station at 2:25 p.m. and Train B passes the same station at 2:55 p.m.
\n" ); document.write( " At this rate, what time will Train B catch up to Train A?
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\n" ); document.write( "from the given information, we know that train B is 30 min (1/2 hr) behind
\n" ); document.write( " train A, when train A passes the station at 2:25PM
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\n" ); document.write( "The distance between the trains at this time: \"1%2F2\" * 50 = 25 mi
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\n" ); document.write( "Let t = time required for train B to catch train A
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\n" ); document.write( "write a distance equation: Dist = speed * time
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\n" ); document.write( "Train B travel dist = Train A travel dist + 25 mi
\n" ); document.write( "50t = 40t + 25
\n" ); document.write( "50t - 40t = 25
\n" ); document.write( "10t = 25
\n" ); document.write( "t = \"25%2F10\"
\n" ); document.write( "t = 2.5 hr or 2 hr 30 min
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\n" ); document.write( "2:25 PM + 2:30 = 4:55 pm, B catches A
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\n" ); document.write( "Check this by finding the travel distance of each train:
\n" ); document.write( "Train B: 50*2.5 = 125 mi
\n" ); document.write( "Train A: 40*2.5 = 100 mi
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\n" ); document.write( "dif in distance: 25 mi
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