document.write( "Question 406792: Find three consecutive positive odd integers such that the square of the smallest exceeds twice the largest by 91.
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Algebra.Com's Answer #286974 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! x , x+2 , and x+4 are the integers\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 91 = 2(x + 4) ___ x^2 - 91 = 2x + 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 2x - 99 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factoring ___ (x - 11)(x + 9) = 0 \n" ); document.write( " |