document.write( "Question 406715: would you please help me to understand how to do this problem?
\n" ); document.write( "I am lost.\r
\n" ); document.write( "\n" ); document.write( "(3x-1)/(2)+(x-3)/(4)=(1)/(2)\r
\n" ); document.write( "\n" ); document.write( "(2x)/(2)+(-2x)/(4)=(1)/(2) multipy by 2 on the 1st term, by -2x on 2nd term?\r
\n" ); document.write( "\n" ); document.write( "x+-2x=(1)/(2)\r
\n" ); document.write( "\n" ); document.write( "3x= (1)/(2)\r
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Algebra.Com's Answer #286965 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( " |multiplying thru by 4
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document.write( "  2(3x-1) + (x-3) = 2
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document.write( "  6x- 2 + x - 3 = 2
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document.write( "       7x -5 = 2
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document.write( "        7x = 7
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document.write( "         x = 1
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document.write( " CHECKING our Answer***
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document.write( "   2/2 + -2/4 = 1/2    \n" );
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