document.write( "Question 406720: In 1993 a farmer owned 250 acres. In 2004 he owned 312 acres. If this growth is linear, how many acres should he own in 2012. Write a linear equation to model his growth. \n" ); document.write( "

Algebra.Com's Answer #286964 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "In 1993 a farmer owned 250 acres.  In 2004 he owned 312 acres.
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document.write( "Using the point-slope formula, 
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document.write( "(2004,312)and
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document.write( "(1993,250) m = 62/11
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document.write( "Using the standard slope-intercept form for an equation of a line y = mx + b
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document.write( "  where m is the slope and b the y-intercept:  
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document.write( " y = (62/11)x + 250   |x is the years beyond 1993
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document.write( "how many acres should he own in 2012  x = 19
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document.write( " y = (62/11)*19 + 250 
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document.write( " y = 107 + 250 = 357 acres \n" );
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