document.write( "Question 406737: How many pounds of a 15% aluminum alloy must be mixed with 500 lb of a 22% aluminum alloy to make a 20% aluminum alloy? \n" ); document.write( "

Algebra.Com's Answer #286957 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x represent the lbs of 15% aluminum
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document.write( "Question states***
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document.write( "  'Mixing' to form (500+x)lbx of 20%
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document.write( " .15x + .22*500 = .20(500+x)
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document.write( "Solving for x
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document.write( "   .02*500= .05x
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document.write( "    .02*500/.05= x =200lb, the amount of 15% aluminum\r
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document.write( "CHECKING our Answer***
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document.write( "  30 + 110 = .20*700 = 140 \n" );
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