document.write( "Question 406730: The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests that, for summer driving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the radiator is 3.6L, how much coolant should be drained and replaced with water to reduce the antifreeze concentration to the recommended level? \n" ); document.write( "

Algebra.Com's Answer #286940 by Edwin McCravy(20056) $\"\"$ $\"About$

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The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests that, for summer driving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the radiator is 3.6L, how much coolant should be drained and replaced with water to reduce the antifreeze concentration to the recommended level?
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document.write( "We start with 3.5 liters of liquid\r\n" );
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document.write( "We drain out x liters of the liquid.\r\n" );
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document.write( "That leaves 3.5-x liters of the liquid.\r\n" );
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document.write( "Those 3.5-x liters of the liquid contains 60% antifreeze.\r\n" );
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document.write( "Therefore those 3.5-x liters of the liquid left in the radiator contain\r\n" );
document.write( ".60(3.5-x) liters of antifreeze.\r\n" );
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document.write( "Now we fill up the radiator with water, and when we do we will have\r\n" );
document.write( "3.5 liters of liquid, and 50% of those 3.5 liters, or .50(3.5) liters,\r\n" );
document.write( "of liquid now will be the .60(3.5-x) liters of antifreeze left in the\r\n" );
document.write( "radiator.\r\n" );
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document.write( "So we set those equal:\r\n" );
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document.write( "       .50(3.5) = .60(3.5-x)\r\n" );
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document.write( "Solve that and get 7/12 of a liter or about .58 liters.\r\n" );
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document.write( "Edwin

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