document.write( "Question 406731: How many liters of a 10% salt solution must be mixed with 15 liters of a 40% salt solution to obtain a 20% salt solution? I have no idea how to set this eqaution up \n" ); document.write( "
Algebra.Com's Answer #286920 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Let x represent represent the amount of 10% solution
\n" ); document.write( "Question states***
\n" ); document.write( "Mixing together to form (15L+x) 20% solution
\n" ); document.write( " .10x + .40*15L = .20(15L+x)
\n" ); document.write( "Solving for x
\n" ); document.write( " .20*15L = .10x
\n" ); document.write( " .20*15L/.10 = x = 30L, the amount of the 10% solution\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 3 + 6 = .20*45 = 9 \n" ); document.write( "
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