document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=406681>Question 406681</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One pump can fill a tank with oil in 10 hours. together with a second pump, it can fill the tank in 6 hours. how long will it take the second peump to fill the tank if it is used alone?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286897 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One pump can fill a tank with oil in 10 hours. together with a second pump, it can fill the tank in 6 hours. how long will it take the second peump to fill the tank if it is used alone?<BR>\n" );
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document.write( "Let x = time (hrs) it takes second pump to fill alone<BR>\n" );
document.write( "then<BR>\n" );
document.write( "6(1/10 + 1/x) = 1<BR>\n" );
document.write( "multiplying both sides by 10x:<BR>\n" );
document.write( "6(x + 10) = 10x<BR>\n" );
document.write( "6x + 60 = 10x<BR>\n" );
document.write( "60 = 4x<BR>\n" );
document.write( "15 hours = x<BR>\n" );
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