document.write( "Question 406663: Which is the value of x when 6x +12 > 0? \n" ); document.write( "
Algebra.Com's Answer #286884 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 6x +12 > 0\r \n" ); document.write( "\n" ); document.write( "add -12\r \n" ); document.write( "\n" ); document.write( "6x>-12 \n" ); document.write( "/6 \n" ); document.write( "x>-2 \n" ); document.write( " \n" ); document.write( " |