document.write( "Question 406663: Which is the value of x when 6x +12 > 0? \n" ); document.write( "
Algebra.Com's Answer #286884 by mananth(16946)\"\" \"About 
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6x +12 > 0\r
\n" ); document.write( "\n" ); document.write( "add -12\r
\n" ); document.write( "\n" ); document.write( "6x>-12
\n" ); document.write( "/6
\n" ); document.write( "x>-2
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