document.write( "Question 406650: Debbie has just enough money to rent a canoe or 1-1/2 hrs. How far out on a lake can she paddle and return on time if she paddles out at 2km/h and back at 4km/h? \n" ); document.write( "
Algebra.Com's Answer #286876 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
\n" ); document.write( "Let d = distance that she travels out and also distance she travels back
\n" ); document.write( "d(out)=d(back)=d\r
\n" ); document.write( "\n" ); document.write( "t (out)=d/2
\n" ); document.write( "t(back)=d/4\r
\n" ); document.write( "\n" ); document.write( "Now we are told that t(out) + t(back) =1.5 hrs
\n" ); document.write( "soooo
\n" ); document.write( "d/2+d/4=1.5
\n" ); document.write( "2d/4+d/4=1.5
\n" ); document.write( "3d/4=1.5 multiply each side by 4
\n" ); document.write( "3d=6
\n" ); document.write( "d=2 mi
\n" ); document.write( "CK
\n" ); document.write( "t(out)=2/2=1 hr
\n" ); document.write( "t(back)=2/4=0.5 hr
\n" ); document.write( "1.5=1.5\r
\n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor
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