document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=406632>Question 406632</A>: <I><SPAN STYLE=\"word-break: break-all;\">    Hi...Can someone please help me with this problem:A 10-m ladder is leaning against a building. The bottom of the ladder is 5m from the building.How high is the top of the building?(To be rounded to the nearest tenths)..Thank you in advance!:) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286869 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The ladder , ground & the wall form a right triangle.\r<BR>\n" );
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document.write( "the ladder is the hypotenuse.\r<BR>\n" );
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document.write( "leg1^2+leg2^2=Hypotenuse^2<BR>\n" );
document.write( "5^2+leg2^2=10^2<BR>\n" );
document.write( "25+leg2^2=100<BR>\n" );
document.write( "leg2^2=100-25<BR>\n" );
document.write( "leg2^2=75<BR>\n" );
document.write( "leg2 = sqrt75<BR>\n" );
document.write( "leg 2= 8.7 feet the height of the wall </SPAN>\n" );
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