document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=406563>Question 406563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Leticia is 21 years older than Katie. In 2 years, Leticia will be twice as old as Katie. Find Leticia's current age and Katie's current age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286862 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286862\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Present age													<BR>\n" );
document.write( "Katie x												<BR>\n" );
document.write( "Leticia	x+21										<BR>\n" );
document.write( "													<BR>\n" );
document.write( "After	2years								<BR>\n" );
document.write( "Katie x	+2										<BR>\n" );
document.write( "Leticia	(x+21+2	)years					<BR>\n" );
document.write( "(x+23)							<BR>\n" );
document.write( "													<BR>\n" );
document.write( "(x+23)=	2(x+2)<BR>\n" );
document.write( "23=2x+4		<BR>\n" );
document.write( "x-2x=4-23		<BR>\n" );
document.write( "-x=-19		<BR>\n" );
document.write( "Katie	age=19years							<BR>\n" );
document.write( "Leticia	age=40years							<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );