document.write( "Question 406604: You invest $12,000 into two diffrent accounts. One account pays 4% annual and the other account pays 2% annual intrest. the intrest earned in one year is $400. how much is invested in each fund? \n" ); document.write( "
Algebra.Com's Answer #286856 by mananth(16946)\"\" \"About 
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You invest $12,000 into two diffrent accounts. One account pays 4% annual and the other account pays 2% annual intrest. the intrest earned in one year is $400. how much is invested in each fund?\r
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\n" ); document.write( "4.00% per annum ------------- x
\n" ); document.write( "2.00% per annum ------------ y
\n" ); document.write( "total investment 12000
\n" ); document.write( "Interest----- $400.00
\n" ); document.write( "...\r
\n" ); document.write( "\n" ); document.write( "x+y=12000 ------------------------1
\n" ); document.write( "4.00%x+2.00%y=$400.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4x+2y=$40,000.00 --------2
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\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
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\n" ); document.write( "-4x-4y =-48000
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "-2y=-$8,000.00
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\n" ); document.write( "divide by -2
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\n" ); document.write( "y=$4,000.00 investment at 2.00%
\n" ); document.write( "Balance $8,000.00 investment at 4.00%
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