document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=406571>Question 406571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation of a line that passes through the point (5,-3) and is perpendicular to the line 4x-7y=11<BR>\n" );
document.write( " 4x -7y=11       slope 4over7    y-y1=m(x-x1)<BR>\n" );
document.write( "                                 <BR>\n" );
document.write( "     7y=4x+11<BR>\n" );
document.write( "     7  7  7<BR>\n" );
document.write( "      y=4+11<BR>\n" );
document.write( "        7  7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286835 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286835\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> slope is 4/7 which is right.\r<BR>\n" );
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document.write( "The perpendicular line will have a slope which is negative reciprocal of  the slope of the given line. <BR>\n" );
document.write( "Since m1*m2=-1\r<BR>\n" );
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document.write( "so slope of the required line will be -7/4\r<BR>\n" );
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document.write( ".. <BR>\n" );
document.write( "line passes through (5,-3)<BR>\n" );
document.write( "plug the value of slope , and the point to find b the y intercept\r<BR>\n" );
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document.write( "-3=(-7/4)*5+b<BR>\n" );
document.write( "-3+35/4=b<BR>\n" );
document.write( "+23/4 = b\r<BR>\n" );
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document.write( "...<BR>\n" );
document.write( "the equation will be y = (-x/4)+23/4 </SPAN>\n" );
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