document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=406473>Question 406473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with my Algebra 2 math homework.  I just need help on one question:  how does one solve: x^2-13x+42=0  <BR>\n" );
document.write( "  <BR>\n" );
document.write( "Here is what I have so far:  Subtract 42 from both sides.  Divide -13 by 2 and square -6.5 to get 42.25.  Add 42.25 to both sides.  Now my equation is <BR>\n" );
document.write( "x^2-13x+42.25=0.25.  <BR>\n" );
document.write( "  Now, how can I factor out the equation to solve it?  <BR>\n" );
document.write( "  Thank you for your help!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286807 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve: <BR>\n" );
document.write( "x^2-13x+42=0<BR>\n" );
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document.write( "Think of two numbers whose product is 42<BR>\n" );
document.write( "and whose sum = -13<BR>\n" );
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document.write( "The numbers are -6 and -7<BR>\n" );
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document.write( "Rewrite the equation replacing -13x by -6x-7x<BR>\n" );
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document.write( "x^2-6x-7x+42 = 0<BR>\n" );
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document.write( "Factor:<BR>\n" );
document.write( "x(x-6)-7(x-6) = 0<BR>\n" );
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document.write( "(x-6)(x-7) = 0<BR>\n" );
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document.write( "x = 6 or x = 7<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== <BR>\n" );
document.write( " </SPAN>\n" );
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