document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=406473>Question 406473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with my Algebra 2 math homework.  I just need help on one question:  how does one solve: x^2-13x+42=0  <BR>\n" );
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document.write( "Here is what I have so far:  Subtract 42 from both sides.  Divide -13 by 2 and square -6.5 to get 42.25.  Add 42.25 to both sides.  Now my equation is <BR>\n" );
document.write( "x^2-13x+42.25=0.25.  <BR>\n" );
document.write( "  Now, how can I factor out the equation to solve it?  <BR>\n" );
document.write( "  Thank you for your help!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286803 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286803\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2-13x+42=0  <BR>\n" );
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document.write( "squaring method\r<BR>\n" );
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document.write( "x^2-13x+169/4 +42=+169/4 \r<BR>\n" );
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document.write( "(x-13/2)^2= 169/4 -42\r<BR>\n" );
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document.write( "(x-13/2)^2= 1/4\r<BR>\n" );
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document.write( "Take the square root on both sides\r<BR>\n" );
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document.write( "(x-13/2) = +/- 1/2<BR>\n" );
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document.write( "x= 13/2 +1/2 = 7<BR>\n" );
document.write( "OR\r<BR>\n" );
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document.write( "x=13/2 -1/2 =6\r<BR>\n" );
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