document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5476>Question 5476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i'm not quite sure how to solve this using substitution.<BR>\n" );
document.write( "x+5y=4<BR>\n" );
document.write( "3x+15y=-1\r<BR>\n" );
document.write( "\n" );
document.write( "Also, does the system have exactly one solution, or more?<BR>\n" );
document.write( "Thanks for helping me! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2868 by </B><A HREF=/tutors/aboutme.mpl?userid=Abbey><B>Abbey(339)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Abbey><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> take the first equation:<BR>\n" );
document.write( "x+5y=5 and put it in terms of x by subtracting 5y from both sides:<BR>\n" );
document.write( "x=5-5y<BR>\n" );
document.write( "then use the second equation and substitute 5-5y in for x<BR>\n" );
document.write( "3x+15y=-1<BR>\n" );
document.write( "3(5-5y)+15y=-1<BR>\n" );
document.write( "eliminate the parentheses, consolidate like terms and solve for y:<BR>\n" );
document.write( "15-15y+15y=-1<BR>\n" );
document.write( "15=-1<BR>\n" );
document.write( "This is not a true statement, so no solution exists. (These are parallel lines and never cross, therefore they don't have an intersection) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );