document.write( "Question 43687: solve for x 2+4(5)^x=16
\n" ); document.write( "Solve for x Log of 7 (5x-1)=2
\n" ); document.write( "Log of 2 (1- x) - Log of 2 (-2x)=3
\n" ); document.write( "Log (-2x)+ Log (3)=Log (96) \n" ); document.write( "
Algebra.Com's Answer #28679 by stanbon(75887)\"\" \"About 
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solve for x: 2+4(5)^x=16
\n" ); document.write( "4(5^x)=14
\n" ); document.write( "5^x=3/5
\n" ); document.write( "Take the log of both sides to get:
\n" ); document.write( "xlog5=log(3/5)
\n" ); document.write( "x=-0.31739381...\r
\n" ); document.write( "\n" ); document.write( "Solve for x: Log of 7 (5x-1)=2
\n" ); document.write( "Assume you mean log(base7)(5x-1)=2
\n" ); document.write( "7^2=5x-1
\n" ); document.write( "49=5x-1
\n" ); document.write( "50=5x
\n" ); document.write( "x=10\r
\n" ); document.write( "\n" ); document.write( "Log of 2 (1- x) - Log of 2 (-2x)=3
\n" ); document.write( "Assume you mean log(base2)(1-x) - log(base2)(-2x)=3
\n" ); document.write( "log(base 2)[(1-x)/-2x]=3
\n" ); document.write( "2^3=[(1-x)/-2x]
\n" ); document.write( "[(1-x)/-2x]=8
\n" ); document.write( "1-x=-16x
\n" ); document.write( "1=-15x
\n" ); document.write( "x=-1/15\r
\n" ); document.write( "\n" ); document.write( "Log (-2x)+ Log (3)=Log (96)
\n" ); document.write( "Log(-6x)=log(96)
\n" ); document.write( "-6x=96
\n" ); document.write( "x=-16
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
\n" );