document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=406396>Question 406396</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many liters of water must be added to 8 liters of 40% acid solution to obtain a 10% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286772 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many liters of water must be added to 8 liters of 40% acid solution to obtain a 10% acid solution?<BR>\n" );
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document.write( "Equation: <BR>\n" );
document.write( "water + water = water<BR>\n" );
document.write( "0.60*8 + 1x = 0.90(8+x)<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "60*8 + 100x = 90*8 + 90x<BR>\n" );
document.write( "10x = 30*8<BR>\n" );
document.write( "x = (1/3)(8)L<BR>\n" );
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document.write( "x = 2 2/3 liters (amt. of water needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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