document.write( "Question 406332: I have a question about linear systems using substitution.
\n" ); document.write( "How do solve:
\n" ); document.write( "x=6-4y
\n" ); document.write( "and
\n" ); document.write( "2x-3y=1
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #286759 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
systems using substitution.
\n" ); document.write( "How do solve:
\n" ); document.write( "x=6-4y
\n" ); document.write( "and
\n" ); document.write( "2x-3y=1
\n" ); document.write( "----
\n" ); document.write( "Substitute for \"x\" and solve for \"y\":
\n" ); document.write( "2(6-4y)-3y = 1
\n" ); document.write( "12-8y-3y = 1
\n" ); document.write( "12-11y = 1
\n" ); document.write( "-11y = -11
\n" ); document.write( "y = 1
\n" ); document.write( "---
\n" ); document.write( "Now solve for \"x\":
\n" ); document.write( "x = 6-4y
\n" ); document.write( "x = 6-4*1
\n" ); document.write( "x = 2
\n" ); document.write( "==========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===========
\n" ); document.write( "
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