document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=406204>Question 406204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 40% alcohol solution must be mixed with a 60 L of a 80% solution to get a 50% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286718 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  How many liters of a 40% alcohol solution must be mixed with a 60 L of a 80% solution to get a 50% solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "alco + alco = alco<BR>\n" );
document.write( "0.80*60 + 0.40x = 0.50(60+x)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply by 100 and solve for \"x\":<BR>\n" );
document.write( "80*60 + 40x = 50*60 + 50x<BR>\n" );
document.write( "-10x = -30*60<BR>\n" );
document.write( "x = (1/3)*60<BR>\n" );
document.write( "x = 20L (amt. of 40% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============== </SPAN>\n" );
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