document.write( "Question 406198: What are the factors to the polynomial:\r
\n" ); document.write( "\n" ); document.write( "f(x)= x^3+2x^2-13x+10 ?\r
\n" ); document.write( "\n" ); document.write( "and what are the factors to this polynomial:\r
\n" ); document.write( "\n" ); document.write( "f(x)= 2x^4+6x^3-2x^2-6x\r
\n" ); document.write( "\n" ); document.write( "and lastly the factors to this polynomial:
\n" ); document.write( "|factored (x^2+2x-3)
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Algebra.Com's Answer #286714 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "f(x)= x^3+2x^2-13x+10 
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document.write( "    x^3+2x^2-13x+10 =0   |Determined x = 1 a root, thus (x-1) a factor
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document.write( "f(x)= (x-1)(x^2+3x-10)   |divided (x^3+2x^2-13x+10) by (x-1)
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document.write( "f(x)= (x-1)(x+5)(x-2)    |factored (x^2+3x-10)
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document.write( "       Note:SUM of the inner product(5x) and the outer product(-2x) = 3x\r
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document.write( "f(x)= 2x^4+6x^3-2x^2-6x 
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document.write( "f(x)= 2x(x^3+3x^2-x-3)  |factoring out the 2x
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document.write( "(x^3+3x^2-x-3) = 0      |Determined x = -1 a root, thus (x+1) a factor
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document.write( "f(x)= 2x(x+1)(x^2+2x-3) |divided (x^3+3x^2-x-3)by (x+1)
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document.write( "f(x)= 2x(x+1)(x+3)(x-1) |factored (x^2+2x-3)
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document.write( "           Note:SUM of the inner product(3x) and the outer product(-x) = 2x\r
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document.write( "(x^2+2x-3)=(x+3)(x-1)\r
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