document.write( "Question 406074: log(2+x)-log(x-3)-log(2)=0 \n" ); document.write( "
Algebra.Com's Answer #286655 by nerdybill(7384)\"\" \"About 
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log(2+x)-log(x-3)-log(2)=0
\n" ); document.write( "log(2+x)/(x-3)-log(2)=0
\n" ); document.write( "log[(2+x)/(x-3)]/2=0
\n" ); document.write( "[(2+x)/(x-3)]/2=10^0
\n" ); document.write( "[(2+x)/(x-3)]/2 = 1
\n" ); document.write( "(2+x)/(x-3) = 2
\n" ); document.write( "(2+x) = 2(x-3)
\n" ); document.write( "2+x = 2x - 6
\n" ); document.write( "2 = x - 6
\n" ); document.write( "8 = x\r
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