document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=406030>Question 406030</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find polar coordinates of each point  (-2sqrt3,2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286637 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find polar coordinates of each point (-2sqrt3,2)<BR>\n" );
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document.write( "The point is in the 2nd quadrant.<BR>\n" );
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document.write( "theta = tan^-1(2/(-2sqrt(3)) = tan^-1(-1/sqrt(3)) = (5pi/6)<BR>\n" );
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document.write( "r = sqrt[(2sqrt(3))^2 + 2^2] <BR>\n" );
document.write( "= sqrt[12+4]<BR>\n" );
document.write( "= 4<BR>\n" );
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document.write( "polar coordinates: (4,5pi/6)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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