document.write( "Question 405996: Hello, could you be so, so nice and help me PLEASE??? Thank you so much.
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document.write( "Alena
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document.write( "When balancing her checkbook, Allison made an error which caused her to show a balance that was $ 54.00 above the actual balance. She had accidently reversed the digits of the amount of one check. The sum of the digits of that check amount was 12.\r
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document.write( "a) write two equations to represent this situation
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document.write( "b) what is the best method to use to solve this system? Why?
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document.write( "c) solve the equations to determine the true amount of the check. \n" );
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Algebra.Com's Answer #286631 by mananth(16946) You can put this solution on YOUR website! let x be ten's place, y in units place \n" ); document.write( "The correct check was 10x+y \n" ); document.write( "This was written as 10y=x \n" ); document.write( ".. \n" ); document.write( "The error was +54 \n" ); document.write( "Original amount - error amount =54\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of the digits =12 \n" ); document.write( "x+y=12 \n" ); document.write( "10x+y-10y+x=54 \n" ); document.write( "9x-9y=54.............1 \n" ); document.write( "x+y=12..............2 \n" ); document.write( "multiply (2) by 9 \n" ); document.write( "we get \n" ); document.write( "9x+9y=108 \n" ); document.write( "Add it to (1) \n" ); document.write( "18x=162 \n" ); document.write( "x= 9 \n" ); document.write( "x+y=12 \n" ); document.write( "y=3\r \n" ); document.write( "\n" ); document.write( "Actual cheque = 93 \n" ); document.write( "error check = 39 \n" ); document.write( "difference = 54 \n" ); document.write( " |