document.write( "Question 406025: Hi, my math book does not explain the \"step by step\" procedure so I don't know how to do each step. Would you please explain how you came up with each answer?
\n" ); document.write( "thank you.\r
\n" ); document.write( "\n" ); document.write( "x^2+x-20=0
\n" ); document.write( "x=-b+-sqrt b(^2-4ac)/(2a)
\n" ); document.write( "x= x sqrt (x^2-4(1)(20))/(2(1))
\n" ); document.write( "x= sqrt (x^2-80)/ (2(1)) Now i am stuck, how to sqrt or factor it\r
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Algebra.Com's Answer #286630 by Tatiana_Stebko(1539)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2%2Bx-20=0\"
\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" till here you were absolutely right
\n" ); document.write( "Look at formula of the quadratic equation \"ax%5E2%2Bbx%2Bc=0\", a, b are coefficients before \"x%5E2\" and \"x\", c is the free term
\n" ); document.write( "so \"a=1\", \"b=1\", \"c=-20\", put in formula
\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1%5E2-4%2A1%2A%28-20%29+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+81+%29%29%2F2+\"
\n" ); document.write( "\"x1+=+%28-1+%2B9%29%2F2+\" or \"x2+=+%28-1+-9%29%2F2+\"
\n" ); document.write( "\"x1+=+4+\" or \"x2+=+-5\"
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