document.write( "Question 405967: A rectangle has a perimeter of 88 ft. The length is 2ft more than twice the width. Find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #286626 by Tatiana_Stebko(1539) $\"\"$ $\"About$

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A perimeter of rectangle is $\"P=2%28W%2BL%29\"$
\n" ); document.write( "If the width is xft, then if the length is 2 ft more than twice the width $\"%282x%29\"$ , so the length is $\"%282x%2B2%29\"$ ft
\n" ); document.write( "Perimeter of this rectangle is $\"P=2%2A%28x%2B%282x%2B2%29%29=2%2A%283x%2B2%29=6x%2B4\"$
\n" ); document.write( "Equation
\n" ); document.write( " $\"6x%2B4=88\"$
\n" ); document.write( " $\"6x=88-4\"$
\n" ); document.write( " $\"6x=84\"$
\n" ); document.write( " $\"x=84%2F6\"$
\n" ); document.write( " $\"x=14\"$
\n" ); document.write( "The width is 14 ft, then the length is $\"%282%2A14%2B2%29=30\"$ ft
\n" ); document.write( "Answer: 14 ft and 30 ft \n" ); document.write( "

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