document.write( "Question 406012: A father is now twice as old as his daughter. 10 years ago he was 3 times as old as her. How old are they both now? \n" ); document.write( "
Algebra.Com's Answer #286620 by J2R2R(94)\"\" \"About 
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f is age of father; d is age of daughter\r
\n" ); document.write( "\n" ); document.write( "Now, f = 2d\r
\n" ); document.write( "\n" ); document.write( "Ten years ago
\n" ); document.write( "(f - 10) = 3(d - 10)\r
\n" ); document.write( "\n" ); document.write( "Replacing f with 2d and expanding
\n" ); document.write( "2d - 10 = 3d - 30
\n" ); document.write( "20 = d
\n" ); document.write( "f = 40\r
\n" ); document.write( "\n" ); document.write( "So the father is now twice the age of his daughter (40 = 2 x 20)
\n" ); document.write( "Ten years ago the father was three times the age of his daughter (30 = 3 x 10)
\n" ); document.write( "The answer is the father is now 40 years and the daughter is 20 years.
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