document.write( "Question 406012: A father is now twice as old as his daughter. 10 years ago he was 3 times as old as her. How old are they both now? \n" ); document.write( "
Algebra.Com's Answer #286620 by J2R2R(94)![]() ![]() You can put this solution on YOUR website! f is age of father; d is age of daughter\r \n" ); document.write( "\n" ); document.write( "Now, f = 2d\r \n" ); document.write( "\n" ); document.write( "Ten years ago \n" ); document.write( "(f - 10) = 3(d - 10)\r \n" ); document.write( "\n" ); document.write( "Replacing f with 2d and expanding \n" ); document.write( "2d - 10 = 3d - 30 \n" ); document.write( "20 = d \n" ); document.write( "f = 40\r \n" ); document.write( "\n" ); document.write( "So the father is now twice the age of his daughter (40 = 2 x 20) \n" ); document.write( "Ten years ago the father was three times the age of his daughter (30 = 3 x 10) \n" ); document.write( "The answer is the father is now 40 years and the daughter is 20 years. \n" ); document.write( " \n" ); document.write( " |