document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=405691>Question 405691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i prove the trig identity? (tan^2X)/secX = secX - cosX </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286612 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do i prove the trig identity? (tan^2X)/secX = secX - cosX<BR>\n" );
document.write( "..<BR>\n" );
document.write( "start with the left side,\r<BR>\n" );
document.write( "\n" );
document.write( "tan^2/sec<BR>\n" );
document.write( "=(sin2/cos^2)/(1/cos)<BR>\n" );
document.write( "=sin^2/cos <BR>\n" );
document.write( "=(1-cos^2)/cos<BR>\n" );
document.write( "=1/cos-cos^2/cos<BR>\n" );
document.write( "=sec-cos<BR>\n" );
document.write( "ans:left-hand side=right-hand side<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );