document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=405945>Question 405945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An executive invests $22,000, some at 6% and some at 4% annual interest. If he receives an annual return of $1080, how much is invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286607 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6% per annum ------  x<BR>\n" );
document.write( "4% per annum--------y\r<BR>\n" );
document.write( "\n" );
document.write( "x+y =22,000....1\r<BR>\n" );
document.write( "\n" );
document.write( "0.06x+0.04y=$1080. <BR>\n" );
document.write( "multiply by 100<BR>\n" );
document.write( "6x+4y=108000............(2)\r<BR>\n" );
document.write( "\n" );
document.write( "multiply (1)-6<BR>\n" );
document.write( "-6x-6y=-132000<BR>\n" );
document.write( "add to (2)<BR>\n" );
document.write( "-2y=-24000<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "y = $12000 ===> at 4%<BR>\n" );
document.write( "Balance $10,000 ay 6%<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );