document.write( "Question 405935: what is the smallest of three positive consecutive odd integers if the product of the second and third integers is 63? \n" ); document.write( "

Algebra.Com's Answer #286604 by algebrahouse.com(1659) $\"\"$ $\"About$

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\"what is the smallest of three positive consecutive odd integers if the product of the second and third integers is 63?\"\r
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\n" ); document.write( "\n" ); document.write( "x = first odd integer
\n" ); document.write( "x + 2 = second odd integer
\n" ); document.write( "x + 4 = 3rd odd integer\r
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\n" ); document.write( "\n" ); document.write( "(x + 2)(x + 4) = 63 {product of second and third is 63}
\n" ); document.write( "x^2 + 6x + 8 = 63 {used foil method}
\n" ); document.write( "x^2 + 6x - 55 = 0 {subtracted 63 from both sides}
\n" ); document.write( "(x + 11)(x - 5) = 0 {factored into two binomials}
\n" ); document.write( "x + 11 = 0 or x - 5 = 0 {set each factor equal to 0}
\n" ); document.write( "x = 5 {first positive odd integer}
\n" ); document.write( "x + 2 = 7 {second positive odd integer}
\n" ); document.write( "x + 4 = 9 {third positive odd integer}\r
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\n" ); document.write( "\n" ); document.write( "5 would be the smallest positive odd integer\r
\n" ); document.write( "\n" ); document.write( "www.algebrahouse.com \n" ); document.write( "

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