document.write( "Question 405935: what is the smallest of three positive consecutive odd integers if the product of the second and third integers is 63? \n" ); document.write( "
Algebra.Com's Answer #286603 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let the consequtive odd integers be n , n+2, n+4\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "(n+2)(n+4)=63
\n" ); document.write( "n^2+6n+8=63
\n" ); document.write( "n^2+6n-55=0
\n" ); document.write( "n^2+11n-5n-55=0
\n" ); document.write( "n(n+11)-5(n+11)=0
\n" ); document.write( "(n+11)(n-5)=0
\n" ); document.write( "n=5 positive integer
\n" ); document.write( "...
\n" ); document.write( "the numbers are 5,7,9
\n" ); document.write( "
\n" );