document.write( "Question 405869: A MESSENGER WALKS 500 FEET IN A LARGE BUILDING FROM THE RECEPTION TO HIS DESTINATION AT THE AVERAGE SPEED FO 4 MILES PER HOURS AND RETURNS TO THE STARTING POINT AT AN AVERAGE SPEED OF 3 MILES PER HOUR. WHAT IS HIS AVERAGE SPEED FOR THE ENTIRE TRIP?? HOW TO CALCULATE? \n" ); document.write( "
Algebra.Com's Answer #286598 by mananth(16946)\"\" \"About 
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time = distance /speed\r
\n" ); document.write( "\n" ); document.write( "1 mile = 5280 feet
\n" ); document.write( "500 feet = 500/5280 miles\r
\n" ); document.write( "\n" ); document.write( "time while going = \"%28500%2F5280%29\"/\"4\" \r
\n" ); document.write( "\n" ); document.write( "Time while returning =\"%28500%2F5280%29\"/\"3\"\r
\n" ); document.write( "\n" ); document.write( "Total time = \"%28500%2F5280%29\"/\"4\" + \"%28500%2F5280%29\"/\"3\"\r
\n" ); document.write( "\n" ); document.write( "Total time = \"500%2F%285280%2A4%29\" + \"500%2F%285280%2A3%29\"\r
\n" ); document.write( "\n" ); document.write( "Total time = \"%28500%2A3%2B500%2A4%29%2F%285280%2A12%29\" \r
\n" ); document.write( "\n" ); document.write( "Total time = 0.055 hours
\n" ); document.write( "...
\n" ); document.write( "speed = distance / time\r
\n" ); document.write( "\n" ); document.write( "speed = (1000/5280) / 0.055\r
\n" ); document.write( "\n" ); document.write( "Average speed of total trip = 3.44 mph\r
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