document.write( "Question 405869: A MESSENGER WALKS 500 FEET IN A LARGE BUILDING FROM THE RECEPTION TO HIS DESTINATION AT THE AVERAGE SPEED FO 4 MILES PER HOURS AND RETURNS TO THE STARTING POINT AT AN AVERAGE SPEED OF 3 MILES PER HOUR. WHAT IS HIS AVERAGE SPEED FOR THE ENTIRE TRIP?? HOW TO CALCULATE? \n" ); document.write( "
Algebra.Com's Answer #286598 by mananth(16946)![]() ![]() You can put this solution on YOUR website! time = distance /speed\r \n" ); document.write( "\n" ); document.write( "1 mile = 5280 feet \n" ); document.write( "500 feet = 500/5280 miles\r \n" ); document.write( "\n" ); document.write( "time while going = \n" ); document.write( "\n" ); document.write( "Time while returning = \n" ); document.write( "\n" ); document.write( "Total time = \n" ); document.write( "\n" ); document.write( "Total time = \n" ); document.write( "\n" ); document.write( "Total time = \n" ); document.write( "\n" ); document.write( "Total time = 0.055 hours \n" ); document.write( "... \n" ); document.write( "speed = distance / time\r \n" ); document.write( "\n" ); document.write( "speed = (1000/5280) / 0.055\r \n" ); document.write( "\n" ); document.write( "Average speed of total trip = 3.44 mph\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |