document.write( "Question 405863: Pls. help me solve this problem.
\n" ); document.write( "The toal of two investments is 25,000. A Part of it was invested at 7 percent and one at 9 percent. The annual interest from the 7 percent investment is $470 more than the 9 percent investment. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #286592 by mananth(16946)\"\" \"About 
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The toal of two investments is 25,000. A Part of it was invested at 7 percent and one at 9 percent. The annual interest from the 7 percent investment is $470 more than the 9 percent investment. How much is invested at each rate?\r
\n" ); document.write( "\n" ); document.write( "A Part 7 percent------------$x
\n" ); document.write( "Part B 9 percent-----------$y
\n" ); document.write( "x+y=25000..........(1)\r
\n" ); document.write( "\n" ); document.write( "Interest from 9 % = 0.09y
\n" ); document.write( "interest from 7% = 0.07x
\n" ); document.write( "0.07x-470=0.09y
\n" ); document.write( "multiply by 100
\n" ); document.write( "7x-47000=9y
\n" ); document.write( "7x-9y=47000......(2)\r
\n" ); document.write( "\n" ); document.write( "multiply (1) by -7
\n" ); document.write( "we get -7x-7y=-175000
\n" ); document.write( "add to (2)
\n" ); document.write( "-16y=-175000+47000
\n" ); document.write( "-16y=-128000
\n" ); document.write( "/-16
\n" ); document.write( "y= $8000 ===> investment at 9%
\n" ); document.write( "Balance $17,000 at 7%
\n" ); document.write( " \n" ); document.write( "
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