document.write( "Question 405860: college algebra - completing the square
\n" ); document.write( "would you help me finish this? I wasn't sure what factors to pick out from 196 so I choose 4 times 49. How do I choose what to use?\r
\n" ); document.write( "\n" ); document.write( "x^2-10x+24=0
\n" ); document.write( "x=-10+-sqrt((-10)^2-4(1)(24))/2(1))
\n" ); document.write( "x=10 +- sqrt((100-(-96))/2)
\n" ); document.write( "x=10 +-sqrt((196)/(2)
\n" ); document.write( "2sqrt(4(49))/2))
\n" ); document.write( "sqrt(2^2(49))/(2)
\n" ); document.write( "2+-sqrt49/2
\n" ); document.write( "2(1+-sqrt49/2)
\n" ); document.write( "1sqrt49\r
\n" ); document.write( "\n" ); document.write( "x=1sqrt49 right?
\n" ); document.write( "

Algebra.Com's Answer #286586 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2-10x%2B24=0\"
\n" ); document.write( "Here's how I do it:
\n" ); document.write( "\"x%5E2+-+10x+=+-24\"
\n" ); document.write( "Take 1/2 of the coefficient of \"x\", square it, and add it
\n" ); document.write( "to both sides.
\n" ); document.write( "\"x%5E2+-+10x+%2B+%28-10%2F2%29%5E2+=+%28-10%2F2%29%5E2+-+24\"
\n" ); document.write( "\"x%5E2+-+10x+%2B+25+=+25+-+24\"
\n" ); document.write( "\"%28x+-+5%29%5E2+=+1\"
\n" ); document.write( "Take the square root of both sides
\n" ); document.write( "\"x+-+5+=+1\"
\n" ); document.write( "\"x+=+6\"
\n" ); document.write( "and, also
\n" ); document.write( "\"x+-+5+=+-1\" (the other square root of 1)
\n" ); document.write( "\"x+=+4\"
\n" ); document.write( "from these, I get \"x-6+=+0\" and \"x-4+=+0\", so
\n" ); document.write( "The factors are
\n" ); document.write( "\"%28x+-+6%29%2A%28x+-+4%29\"\r
\n" ); document.write( "\n" ); document.write( "
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