document.write( "Question 405848: Find the value of z such that approximately 13.31% of the distribution lies between it and the mean. \n" ); document.write( "
Algebra.Com's Answer #286572 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the value of z such that approximately 13.31% of the distribution lies between it and the mean. \n" ); document.write( "---- \n" ); document.write( "Draw a normal curve and put the mean in the middle. \n" ); document.write( "--- \n" ); document.write( "Shade an area of 13.31% to the left of the mean. \n" ); document.write( "That has a left tale of 50-13.31 = 36.69% \n" ); document.write( "----- \n" ); document.write( "Find the z-value with a left tail of 36.69%: \n" ); document.write( "--- \n" ); document.write( "z = invNorm(0.3669) = -0.3401 \n" ); document.write( "=============================== \n" ); document.write( "Similarly, if you shade the area on the \n" ); document.write( "right side of the mean you will get a \n" ); document.write( "z-value of +0.3401 \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |