document.write( "Question 405848: Find the value of z such that approximately 13.31% of the distribution lies between it and the mean. \n" ); document.write( "
Algebra.Com's Answer #286572 by stanbon(75887)\"\" \"About 
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Find the value of z such that approximately 13.31% of the distribution lies between it and the mean.
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\n" ); document.write( "Draw a normal curve and put the mean in the middle.
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\n" ); document.write( "Shade an area of 13.31% to the left of the mean.
\n" ); document.write( "That has a left tale of 50-13.31 = 36.69%
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\n" ); document.write( "Find the z-value with a left tail of 36.69%:
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\n" ); document.write( "z = invNorm(0.3669) = -0.3401
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\n" ); document.write( "Similarly, if you shade the area on the
\n" ); document.write( "right side of the mean you will get a
\n" ); document.write( "z-value of +0.3401
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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