document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=405667>Question 405667</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose a robot has a straight arm 18 inches long, that can rotate about the origin in a coordinate plane. If the robot’s hand is at first located at the point (18, 0) and then rotates through an angle of 60 degrees, what’s the new location (i.e. coordinates) of the hand? (Show calculations and a draw diagram.)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286489 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose a robot has a straight arm 18 inches long, that can rotate about the origin in a coordinate plane. If the robot’s hand is at first located at the point (18, 0) and then rotates through an angle of 60 degrees, what’s the new location (i.e. coordinates) of the hand?<BR>\n" );
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document.write( "Radius = 18<BR>\n" );
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document.write( "After rotation DATA:<BR>\n" );
document.write( "x = r*cos(60) = 18*(1/2) = 9<BR>\n" );
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document.write( "y = r*sin(60) = 18*Sqrt(3)/2 = 9sqrt(3)<BR>\n" );
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document.write( "New Location: (9,9sqrt(3))<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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