document.write( "Question 405580: I am needing some help with this...\r
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Algebra.Com's Answer #286454 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"10a%5E2%2B25a-15\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"5%282a%5E2%2B5a-3%29\" Factor out the GCF \"5\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's focus on the inner expression \"2a%5E2%2B5a-3\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"2a%5E2%2B5a-3\" we can see that the first term is \"2a%5E2\" and the last term is \"-3\" where the coefficients are 2 and -3 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 2 and the last coefficient -3 to get -6. Now what two numbers multiply to -6 and add to the middle coefficient 5? Let's list all of the factors of -6:\r
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\n" ); document.write( "\n" ); document.write( "Factors of -6:\r
\n" ); document.write( "\n" ); document.write( "1,2,3,6\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to -6\r
\n" ); document.write( "\n" ); document.write( "(1)*(-6)\r
\n" ); document.write( "\n" ); document.write( "(2)*(-3)\r
\n" ); document.write( "\n" ); document.write( "(-1)*(6)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(3)\r
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\n" ); document.write( "\n" ); document.write( "note: remember, the product of a negative and a positive number is a negative number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 5? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 5\r
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First NumberSecond NumberSum
1-61+(-6)=-5
2-32+(-3)=-1
-16-1+6=5
-23-2+3=1
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\n" ); document.write( "\n" ); document.write( "From this list we can see that -1 and 6 add up to 5 and multiply to -6\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"2a%5E2%2B5a-3\", replace \"5a\" with \"-a%2B6a\" (notice \"-a%2B6a\" adds up to \"5a\". So it is equivalent to \"5a\")\r
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\n" ); document.write( "\n" ); document.write( "\"2a%5E2%2Bhighlight%28-a%2B6a%29-3\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"2a%5E2-a%2B6a-3\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%282a%5E2-a%29%2B%286a-3%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"a%282a-1%29%2B3%282a-1%29\" Factor out the GCF of \"a\" out of the first group. Factor out the GCF of \"3\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28a%2B3%29%282a-1%29\" Since we have a common term of \"2a-1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"2a%5E2-a%2B6a-3\" factors to \"%28a%2B3%29%282a-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"2a%5E2%2B5a-3\" factors to \"%28a%2B3%29%282a-1%29\" (since \"2a%5E2%2B5a-3\" is equivalent to \"2a%5E2-a%2B6a-3\")\r
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\n" ); document.write( "\n" ); document.write( "So our expression goes from \"5%282a%5E2%2B5a-3%29\" and factors further to \"5%28a%2B3%29%282a-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So \"10a%5E2%2B25a-15\" factors to \"5%28a%2B3%29%282a-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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\n" ); document.write( "\n" ); document.write( "Jim
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