document.write( "Question 405565: what is the first three terms of the sequence 6n-5? \n" ); document.write( "
Algebra.Com's Answer #286452 by MathLover1(20850)\"\" \"About 
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\"S+=+6n-5\"\r
\n" ); document.write( "\n" ); document.write( "Work out the first three terms of this sequence\"\r
\n" ); document.write( "\n" ); document.write( "The first three terms are found by substituting \"n\" with \"1\" (first term), \"2\" (second term) and \"3\" (third term)\r
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\n" ); document.write( "\n" ); document.write( "so\r
\n" ); document.write( "\n" ); document.write( "\"n=1\" gives: \"S=6%2A1-5+=+6-5+=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"n=2\" gives: \"S=6%2A2-5=+12-5+=+7\"\r
\n" ); document.write( "\n" ); document.write( "\"n=3\" gives: \"S=6%2A3-5+=+18-5+=+13\"\r
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\n" ); document.write( "\n" ); document.write( "So the first three terms of S are \"1\", \"7\" and \"13\".
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