document.write( "Question 405575: Find the equation of the line.
\n" ); document.write( "Thru (4,2) ; m= -2/3\r
\n" ); document.write( "\n" ); document.write( "Thru (9,2) ; perpendicular to 3x+2y=31
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Algebra.Com's Answer #286450 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Using the standard slope-intercept form for an equation of a line y = mx + b
\n" ); document.write( " where m is the slope and b the y-intercept. \r
\n" ); document.write( "\n" ); document.write( "Line thru (4,2) where m= -2/3
\n" ); document.write( " y = (-2/3)x + b |using ordered pair Pt(4,2) to solve for b
\n" ); document.write( " 2 = -8/3 + b
\n" ); document.write( " 14/3 = b
\n" ); document.write( "y = (-2/3)x + 14/3 |standard form: 2x + 3y = 14\r
\n" ); document.write( "\n" ); document.write( "Thru (9,2)and 'perpendicular' to 3x+2y=31 OR y = (-3/2)x +31/2
\n" ); document.write( "slope of line perpendicular to it would be 2/3. (negative reciprocal)
\n" ); document.write( " y = (2/3)x + b |using ordered pair Pt(9,2) to solve for b
\n" ); document.write( " 2 = 6 + b
\n" ); document.write( " -4 = b
\n" ); document.write( " y = (2/3)x -4 \n" ); document.write( "
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