document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=405537>Question 405537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the easier way of finding the fourth positive root of 81    Do I have to start at 2 then move on to my three's, or is there a formula that will shorten this process? Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286420 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the easier way of finding the fourth positive root of 81 Do I have to start at 2 then move on to my three's, or is there a formula that will shorten this process? <BR>\n" );
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document.write( "Form the prime factor form:<BR>\n" );
document.write( "81 = 3*27<BR>\n" );
document.write( "= 3*3*9<BR>\n" );
document.write( "= 3*3*3*3<BR>\n" );
document.write( "= 3^4<BR>\n" );
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document.write( "So the 4th root is 3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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