document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=405537>Question 405537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the easier way of finding the fourth positive root of 81    Do I have to start at 2 then move on to my three's, or is there a formula that will shorten this process? Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286419 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you mean the principal root, it's +3<BR>\n" );
document.write( "There are 4 th roots.<BR>\n" );
document.write( "-3, +3, 3i and -3i<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=81%5E%281%2F4%29+=+sqrt%28sqrt%2881%29%29+=+sqrt%289%29 ALIGN=MIDDLE  ALT=\"81%5E%281%2F4%29+=+sqrt%28sqrt%2881%29%29+=+sqrt%289%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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