document.write( "Question 405513: what is the factor of 10y^3+5y^2-15y\r
\n" ); document.write( "\n" ); document.write( "I just can't get this one \n" ); document.write( "

Algebra.Com's Answer #286410 by Tatiana_Stebko(1539) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"10y%5E3%2B5y%5E2-15y=5y%2A%282y%5E2%2By-3%29\"$
\n" ); document.write( "Use method $\"ax%5E2%2Bbx%2Bc=a%28x-x1%29%28x-x2%29\"$ , when $\"x1\"$ , $\"x2\"$ - are the roots of the quadratic equations $\"ax%5E2%2Bbx%2Bc=0\"$
\n" ); document.write( " $\"2y%5E2%2By-3=2%28y-y1%29%28y-y2%29\"$
\n" ); document.write( " $\"2y%5E2%2By-3=0\"$
\n" ); document.write( " $\"y=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( " $\"y=+%28-1+%2B-+sqrt%28+1%5E2-4%2A2%2A%28-3%29+%29%29%2F%282%2A2%29+\"$
\n" ); document.write( " $\"y1=+%28-1+%2Bsqrt%28+25+%29%29%2F4+\"$ or $\"y2=+%28-1+-sqrt%28+25+%29%29%2F4+\"$
\n" ); document.write( " $\"y1=1+\"$ or $\"y2=-1.5+\"$
\n" ); document.write( " $\"2y%5E2%2By-3=2%28y-1%29%28y-%28-1.5%29%29=2%28y-1%29%28y%2B1.5%29=%28y-1%29%282y%2B3%29\"$
\n" ); document.write( ".
\n" ); document.write( " $\"10y%5E3%2B5y%5E2-15y=5y%2A%282y%5E2%2By-3%29=5y%28y-1%29%282y%2B3%29\"$ \n" ); document.write( "

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