document.write( "Question 405447: I need help with this problem please:\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangular patio is three feet less than twice the width. The perimeter of the patio is ninety feet. Find the length and width.
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Algebra.Com's Answer #286386 by mananth(16946)\"\" \"About 
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width =x
\n" ); document.write( "length=2x-3
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\n" ); document.write( "\n" ); document.write( "Perimeter = 2*(L+W)
\n" ); document.write( "2*(x+2x-3)=90
\n" ); document.write( "2(3x-3)=90
\n" ); document.write( "/2
\n" ); document.write( "3x-3=45
\n" ); document.write( "+3
\n" ); document.write( "3x=48
\n" ); document.write( "/3
\n" ); document.write( "x=16feet ===>width\r
\n" ); document.write( "\n" ); document.write( "length = 2x-3===> 2*16-3=29feet
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