document.write( "Question 405447: I need help with this problem please:\r
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document.write( "The length of a rectangular patio is three feet less than twice the width. The perimeter of the patio is ninety feet. Find the length and width. \n" );
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Algebra.Com's Answer #286386 by mananth(16946)![]() ![]() You can put this solution on YOUR website! width =x \n" ); document.write( "length=2x-3 \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "Perimeter = 2*(L+W) \n" ); document.write( "2*(x+2x-3)=90 \n" ); document.write( "2(3x-3)=90 \n" ); document.write( "/2 \n" ); document.write( "3x-3=45 \n" ); document.write( "+3 \n" ); document.write( "3x=48 \n" ); document.write( "/3 \n" ); document.write( "x=16feet ===>width\r \n" ); document.write( "\n" ); document.write( "length = 2x-3===> 2*16-3=29feet \n" ); document.write( " |