document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=405482>Question 405482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle, find the measures in degrees of all three angles if the measure of the second angle is four times the measure of the first, and the third angle is 45 degrees more than the second. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286378 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first angle =x<BR>\n" );
document.write( "second angle = 4x<BR>\n" );
document.write( "third angle = 4x+45\r<BR>\n" );
document.write( "\n" );
document.write( "...<BR>\n" );
document.write( "x+4x+4x+45=180<BR>\n" );
document.write( "9x+45=180<BR>\n" );
document.write( "add -45<BR>\n" );
document.write( "9x=135<BR>\n" );
document.write( "x=15 ===> first angle<BR>\n" );
document.write( "4x=4*15=60===>second angle<BR>\n" );
document.write( "4x+45= 4*15+45=105====>third angle </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );