document.write( "Question 405308: For which value or values of k, if any, does the quadratic equation in x,
\n" ); document.write( "(k-8)x^2+kx -1 = 0 have exactly one solution?
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Algebra.Com's Answer #286372 by ankor@dixie-net.com(22740)\"\" \"About 
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For which value or values of k, if any, does the quadratic equation in x,
\n" ); document.write( "(k-8)x^2+kx -1 = 0 have exactly one solution?
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\n" ); document.write( "We know that when the discriminant = 0, we have a single value for the roots
\n" ); document.write( "b^2 - 4*a*c = 0
\n" ); document.write( "In this equation a = (k-8), b = k, c = -1
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\n" ); document.write( "k^2 - (4*(k-8)*-1) = 0
\n" ); document.write( ":
\n" ); document.write( "k^2 - (-4(k-8))
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\n" ); document.write( "k^2 - (-4k + 32)
\n" ); document.write( "Remove brackets, change the signs
\n" ); document.write( "k^2 + 4k - 32 = 0
\n" ); document.write( "factors to
\n" ); document.write( "(k+8)(k-4) = 0
\n" ); document.write( "two values for k
\n" ); document.write( "k = -8
\n" ); document.write( "k = +4
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\n" ); document.write( "we can prove this
\n" ); document.write( "k=-8
\n" ); document.write( "(-8-8)x^2 - 8x - 1 = 0
\n" ); document.write( "-16x^2 - 8x - 1 = 0
\n" ); document.write( "Multiply by -1
\n" ); document.write( "16x^2 + 8x + 1 = 0
\n" ); document.write( "factors to
\n" ); document.write( "(4x + 1)(4x + 1) = 0
\n" ); document.write( "4x = -1
\n" ); document.write( "x = \"-1%2F4\" a double root with one value
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\n" ); document.write( "and for k = 4
\n" ); document.write( "(4-8)x^2 + 4x - 1 = 0
\n" ); document.write( "-4x^2 + 4x - 1 = 0
\n" ); document.write( "Multiply by -1
\n" ); document.write( "4x^2 - 4x + 1 = 0
\n" ); document.write( "factors to
\n" ); document.write( "(2x - 1)(2x - 1) = 0
\n" ); document.write( "2x = 1
\n" ); document.write( "x = \"1%2F2\" a double root with one value
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\n" ); document.write( "We can say: k=-8 or k=4 will give one solution for the equation
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