document.write( "Question 405454: please help me solve this problem : a boat takes 45 minutes to get 6 miles downstream and 1 hour to get back. find the speed of the boat in still water and the speed of the current. \n" ); document.write( "
Algebra.Com's Answer #286364 by mananth(16946) You can put this solution on YOUR website! speed of boat in still water = x mph \n" ); document.write( "speed of current = y mph \n" ); document.write( ".. \n" ); document.write( "speed upstream = x-y \n" ); document.write( "speed downstream = x+y \n" ); document.write( "... \n" ); document.write( "time upstream = 1 hour \n" ); document.write( "time downstream = 3/4 hours \n" ); document.write( ".. \n" ); document.write( "distance = 6 miles\r \n" ); document.write( "\n" ); document.write( "time= distance /speed \n" ); document.write( "6/x-y= 1 \n" ); document.write( "x-y=6......1 \n" ); document.write( "... \n" ); document.write( "6/x+y = 3/4 \n" ); document.write( "4*6= 3(x+y) \n" ); document.write( "24 = 3(x+y) \n" ); document.write( "/3 \n" ); document.write( "8=x+y......2 \n" ); document.write( "add (1)&(2) \n" ); document.write( "2x=14 \n" ); document.write( "x=14/2 \n" ); document.write( "x= 7 mph ===> speed of boat \n" ); document.write( ".. \n" ); document.write( "x-y =6 \n" ); document.write( "7-y=6 \n" ); document.write( "y=1 mph speed of current \n" ); document.write( " |