document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=405415>Question 405415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are complementary. the sum of the measure of the first angle and half the second angle is 77 degrees. find the measure of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286334 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286334\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two angles are complementary. the sum of the measure of the first angle and half the second angle is 77 degrees. find the measure of the angles.<BR>\n" );
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document.write( "let x=first angle<BR>\n" );
document.write( "then 90-x=second angle (since angles are complementary)<BR>\n" );
document.write( "x+(1/2)(90-x)=77<BR>\n" );
document.write( "x+45-x/2=77<BR>\n" );
document.write( "2x+90-x=154<BR>\n" );
document.write( "x=154-90<BR>\n" );
document.write( "x=64<BR>\n" );
document.write( "90-x=26<BR>\n" );
document.write( "..<BR>\n" );
document.write( "ans:\r<BR>\n" );
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document.write( "The first angle=64 deg<BR>\n" );
document.write( "The second angle=26 deg </SPAN>\n" );
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