document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=405391>Question 405391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what are 2 supplementary angels if one is 5 times the other?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286329 by </B><A HREF=/tutors/aboutme.mpl?userid=IWork4Dessert><B>IWork4Dessert(60)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=IWork4Dessert><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=IWork4Dessert><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Supplementary angles are two angles whose values, when added up, equal 180º. <BR>\n" );
document.write( "You know that one of your angles is 5 times the other angle, and you know that together they must be 180. <BR>\n" );
document.write( "Let's have the first angle be \"x\". That means that the other angle would be \"5x\". <BR>\n" );
document.write( "Now all you have to do is make an equation. <BR>\n" );
document.write( "(x)+(5x)=180<BR>\n" );
document.write( "6x=180<BR>\n" );
document.write( "x=30<BR>\n" );
document.write( "Your first angle is 30. Now multiply it by 5 to get the 5x. <BR>\n" );
document.write( "5x=150<BR>\n" );
document.write( "30+150=180<BR>\n" );
document.write( "And it works. Questions? Let me know!<BR>\n" );
document.write( "Hope this helps :) </SPAN>\n" );
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